The radius of the bromide ion is 0.182 nm. According to the radius ratio rule the largest cation that can fit in tetrahedral hole has radius

Options

A. `7.53times10^(-2)nm`
B. `1.82times10^(-1)nm`
C. `7.53times10^(-1)nm`
D. `1.82times10^(-2)nm`

Answer

A

Explanation

For a cation to fit in a tetrahedral hole
`0.225le(r^(+))/r^(-)lt0.414`
`0.225le(r^(+))/(0.182)lt0.414`
Radius of the largest cation
`r^(+)lt0.414times0.182`nm
=`0.07535"nm"=7.535times10^(-2)`nm
`therefore` Largest cation in choice (A).