The radius of a divaent cation `A^(2+)` is 94pm and of divalent anion `B^(2-)` is 146pm. The compound AB has:

Options

A. rock salt structure
B. zinc blende structure
C. antifluorite structure
D. cesium chloride like structure

Answer

A

Explanation

`(r^(+))/(r^(-))=94/146=0.644`
Thus, `0.414le(r^(+))/(r^(-))lt 0.732`
`therefore` The ionic solid is expected to have NaCl type (rock salt type) structure.