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The C.N.of A(2+) in AB(2) is 8, then C.N...

The C.N.of `A_(2+)` in `AB_(2)` is 8, then C.N. of B is

A

8

B

6

C

4

D

2

Text Solution

Verified by Experts

The correct Answer is:
C
In `AB_(2)`,
`C.N. of B =1/2timesC.N." of "A`
=`1/2times8=4`
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