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Only those atoms which form four covalen...

Only those atoms which form four covalent bonds produce a repetitive three dimensional structure using only covalent bonds, e.g., diamond structure. The latter is based on an fcc lattice where four out of the eight tetrahedral holes are occupied by carbon atoms. Every atom in this structure is surrounded tetrahedrally by four others. Germanium, silicon and grey tin also crystallize in the same way as diamond
`("Given " sin 54^(@) 44'=0.8164)`
If the edge length is same,density of carbon atom is

A

`3.42 g//c c`

B

`2.40 g//c c`

C

`1.63 g//c c`

D

`2.58 g//c c`

Text Solution

Verified by Experts

The correct Answer is:
A
`d=(8times12)/(6.02times10^(23)timesa^(3))`
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How many tetrahedral holes are occupied in diamond ?

In diamond structure ,carbon atoms form fcc lattic and 50% tetrahedral voids occupied by acrbon atoms . Evergy carbon atoms is surrounded tetrachedral by four carbon atom with bond length 154 pm . Germanium , silicon and grey tin also crystallise in same way as diamond (N_(A)=6xx 10^(23)) The side length of diamond unit cell is ("in pm") :

In diamond structure ,carbon atoms form fcc lattic and 50% tetrahedral voids occupied by acrbon atoms . Evergy carbon atoms is surrounded tetrachedral by four carbon atom with bond length 154 pm . Germanium , silicon and grey tin also crystallise in same way as diamond (N_(A)=6xx 10^(23)) The mass of diamond unit cell is: