Home
Class 11
CHEMISTRY
The edge length of LiCl (NaCl structur...

The edge length of LiCl (NaCl structure) unit cell is 514 pm. Assuming anion-contact, the ionic radius of `Cl^(-)`ion is

A

128.5 pm

B

257 pm

C

181.7 pm

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
Face diagonal =`sqrt2a=sqrt2times514 "pm"`
`therefore" "4r=sqrt2times514"pm"`
`Rightarrow" "r=(sqrt2times512)/4"pm"=181.7"pm"`
Promotional Banner

Topper's Solved these Questions

  • STATES OF MATTER (SOLID STATE CHEMISTRY)

    DINESH PUBLICATION|Exercise REASON ASSERTION TYPE MCQs|8 Videos

  • STATE OF MATTER (GASEOUS AND LIQUID STATE)

    DINESH PUBLICATION|Exercise Ulitmate Preparatory package|20 Videos

  • STATES OF MATTER : GASES AND LIQUIDS

    DINESH PUBLICATION|Exercise Statement Type Question|5 Videos

Similar Questions

Explore conceptually related problems

The unit cell cube length for LiCl(just like NaCl structures) is 5.14Å . Assuming anion-anion contact, the ionic radius for chloride ion is:

The unit cube length for LiCl ( NaCl structure) is 5.14 Å . Assuming anion-anion contact, calculate the ionic radius for chloride ion.

The unit cube length for LiCl(NaCl structure) is 5.14overset(@)A . Assuming anion-anion contract, calculate the ionic radius for chloride ion overset(@)A is

Edge length of M^(+)X (fcc structure) is 7.2Å . Assuming ( M^(+) - X^(-)) contact along the cell edge, radius of X^(-) ion is ( r_(M+) = 1.6Å):

LiCl has rock salt structure, with an edge length of 6.0Å. If anions are in contact, the ionic radius of chloride ion is