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For a chemical reaction A rarr B, it is...

For a chemical reaction `A rarr B`, it is found that the rate of reaction doubles when the concentration of `A` is increased `4` times. What is the order of reaction ? Suggest the rate law also.

A

4

B

0

C

`1//2`

D

1

Text Solution

Verified by Experts

The correct Answer is:
C

`r=k[A]^(n)`
`2r=k[4A]^(n)`
Dividing (ii) by (i) `(2r)/(r)=(k)/(k)[(4A)/(A)]^(n)`
or `2=2^(2n)or 2n=1or n=1//2`
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