For hypothetical chemical reaction `A rarr I`, it is found that the reaction is third order in `A`. What happens to the rate of reaction when the concentration of `A` is doubled?

Options

A. Rate increases by a factor of 2
B. Rate decreases by a factor of 3
C. Rate increases by a factor of 8
D. Rate remains unaffected

Answer

C

Explanation

`r_(1)=k[A]^(3)therefore` conc. Of A is doubled i.e., 2A
`r_(2)=k[2A]^(3)=k.8[A]^(3)=8r_(1)`