In acidic medium the rate of reaction between `(BrO_(3))^(-)` and `Br^(-)` ions is given by the expression `-(d(BrO_(3)^(-)))/(dt)=k[BrO_(3)^(-)][Br^(-)][H^(+)]^(2)` it means

Options

A. rate constant of overall reaction is 4 `sec^(-1)`
B. rate of reaction is independent of the conc. Of acid
C. the change in pH of the solution will not affect the rate
D. doubling the conc. Of `H^(+)` ions will increase the reaction rate by 4 times

Answer

D

Explanation

Since the rate law contains `[H^(+)]` term. This means that rate changes variation in the value of pH.