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The rate constant of a reaction is 3.25x...

The rate constant of a reaction is `3.25xx10^(-3) "mol"^(-2) "litre"^(2) "min"^(-1)` The order of reaction is

A

zero

B

1

C

2

D

3

Text Solution

Verified by Experts

The correct Answer is:
D
For a third order reaction r = `k[A]^(3)`
`therefore" k"=(r)/([A]^(3))=("mol. L"^(-1).s^(-1))/(("mol. L"^(-1))^(3))`
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