Rate constant `k = 1.2 xx 10^(3) mol^(-1) L s^(-1)` and `E_(a) = 2.0 xx 10^(2) kJ mol^(-1)`. When `T rarr oo`:

Options

A. `2.0xx10^(2)` kJ `"mol"^(-1)`
B. `1.2xx10^(3) "mol"^(-1)L s^(-1)`
C. `1.2xx10^(3)` mol `L^(-1) s^(-1)`
D. `2.4xx10^(3)` kJ `"mol"^(-1) s^(-1)`

Answer

B

Explanation

`k=A.e^(-E_(a)//RT)=-A//e^(-E_(a)//RT)`
When `Trarr proprArr(1)/(T)rarr0`
`hArr" "(E_(a))/(RT)rarr0rArr._(e)E_(a)//RT)rarr1`
Thus, when `Trarroo`
`A= k 1.2cc10^(3)"mol"^(-1)"L s"^(-1)`