If initial concentration is doubled, the time for half-reaction is also doubled, the order of reaction is

Options

A. zero
B. first
C. second
D. third

Answer

A

Explanation

`t_(1//2)prop(1)/("(conc. of reactant)"^(n-1))`
For zero order, n = 0
The half life period `prop` (conc. of reactant).
In the question, the time for half reaction is doubled when initial concentration is doubled it is zero reaction.