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75% of a first-order reaction was comple...

`75%` of a first-order reaction was completed in `32` minutes, when was `50%` of the reaction completed ?

A

16 minutes

B

24 minutes

C

8 minutes

D

4 minutes

Text Solution

Verified by Experts

The correct Answer is:
A
`k=(2.303)/(t)log_(10)((a)/(a-x))`
`k=(2.303)/(32)log_(10)((100)/(100-75))`….(i)
`k=(2.303)/(t)log((100)/(100-50))`….(ii)
From the two eqns. (i) and (ii)
t = 16 minutes.
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