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The conversion of A rarr B follows secon...

The conversion of `A rarr B` follows second-order kinetics. Doubling the concentration of `A` will increase the rate of formation of `B` by a factor

A

2

B

`1//2`

C

4

D

`1//4`

Text Solution

Verified by Experts

The correct Answer is:
C
`r = k [A]^(2)`.
When concentration is doubled
`r = k[2A]^(2)=k 4[A]^(2)`.
The new rate becomes 4 times.
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