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Select the law that corresponds to data shown for the following reaction `A+B rarr` Products
`{:(Exp,[A],[B],"Initial rate",),(1,0.012,0.035,0.1,),(2,0.024,0.070,0.8,),(3,0.024,0.035,0.1,),(4,0.012,0.070,0.8,):}`

A

rate `=k[B]^(3)`

B

rate `=k[B]^(4)`

C

rate `=k[A] [B]^(3)`

D

rate `=k[A]^(2)[B]^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
From exp. And 2 + 3 we find that changing conc. of A does not change the rate
`therefore` reaction is zero order w.r.t. A. From exp. 1 and 4
`(0.1)/(0.8)=(R[0.035]^(x))/(k[0.070]^(x))` or `(0.5)^(x)=0.125`
i.e., `(0.5)^(x)=(0.5)^(3)`. Hence x = 3.
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