For a chemical reaction `A rarr B`, it is found that the rate of reaction doubles when the concentration of `A` is increased `4` times. What is the order of reaction ? Suggest the rate law also.

Options

A. Two
B. One
C. Half
D. Zero

Answer

C

Explanation

Let Rate `= k [A]^(n)`
`r_(1)=k d^(n)`
`r_(2) = k (4a)^(n)`
But `r_(2)//r_(1)=2`
`therefore n = 1//2`
`therefore` order of reaction = 1/2