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The first order rate constant for the de...

The first order rate constant for the decomposition of `N_(2)O_(5)` is `6.2 xx 10^(-4) sec^(-1)`. The `t_(1//2)` of decomposition is

A

1117.2

B

111.7

C

223.4

D

160.9

Text Solution

Verified by Experts

The correct Answer is:
A
`t_(1//2)=(0.693)/(k)=(0.693)/(6.2xx10^(-4)s^(-1)) = 1117.7`
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DINESH PUBLICATION-RATES OF REACTIONS AND CHEMICAL KINETICS-Revision Question
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