For a first order reaction, obatin a positive slope, we need to plot [A] in the concentration of reactant AB

Options

A. `log_(10)[A]vst`
B. `-log_(e)[A]vs t`
C. `log_(10)[A]vs log t`
D. `[A] vs t`

Answer

B

Explanation

For a first order reaction `[A]=[A_(0)].e^(-kt)`
`therefore log_(e )[A]=ln_(e )[A_(0)]-kt`
or `-ln_(e )[A]=kt-ln[A_(0)]`
`therefore` Plot of `ln_(e )(A)` gives a line with positive slope.