The reaction `2N_(2)O_(5)hArr 2N_(2)O_(4)+O_(2)` is

Options

A. Biomolecular and second order
B. Unimolecular and first order
C. Bimolecular and first order
D. Biomolecular and zero order

Explanation

To determine the type of reaction for the equation \(2N_{2}O_{5} \rightleftharpoons 2N_{2}O_{4} + O_{2}\), we need to analyze its molecularity and order.

### Step 1: Identify Molecularity
Molecularity refers to the number of reactant molecules involved in an elementary reaction step. In the given reaction, we have:

- 2 molecules of \(N_{2}O_{5}\) reacting to form products.

Since two molecules of \(N_{2}O_{5}\) are involved in the reaction, the molecularity of this reaction is **2**. This classifies the reaction as **bimolecular**.

### Step 2: Determine Reaction Order
The order of a reaction is determined experimentally and reflects how the rate of reaction depends on the concentration of the reactants.

1. The reaction is not elementary because it occurs in more than one step.
2. Therefore, we cannot directly infer the order from the balanced equation.
3. Experimental data is required to determine the reaction order.

In this case, it has been experimentally determined that the reaction order is **1**.

### Conclusion
- **Molecularity**: 2 (Bimolecular)
- **Order**: 1 (First Order)

Thus, the correct classification of the reaction is that it is **bimolecular and first order**.

### Final Answer
The reaction \(2N_{2}O_{5} \rightleftharpoons 2N_{2}O_{4} + O_{2}\) is **bimolecular (molecularity = 2)** and **first order (order = 1)**.

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