A substance undergoes first order decomposition. The decomposition follows two parallel first order reaction as:
and `KP_(1)=1.26xx10^(-4)sec^(-1)`
`K_(2)=3.80xx10^(-5)sec^(-1)`
The percentage distribution of B and C are:

Options

A. 75 % B and 25 % C
B. 80 % B and 20 % C
C. 60 % B and 40 % C
D. 76.83 % B and 23.17 % C

Answer

D

Explanation

`("Rate of formation of B")/("Rate of formation of C")=(1.26xx10^(-4))/(38xx10^(-5))=(12.6)/(3.8)`
`([B])/([C])=(126)/(38)`
% of `B=(126)/(164)xx100=76.83%`
% of `C=100-76.83=23.17%`