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The rate constant of a second order reac...

The rate constant of a second order reactions
`2A rarr` Products, is `10^(-4) "lit mol"^(-1) "min"^(-1)`. The initial concentration of the reactant is `10^(-2) "mol lit"^(-1)`. What is the half life (in min) ?

A

10

B

1000

C

100

D

`10^(6)`

Text Solution

Verified by Experts

The correct Answer is:
D
Half life period of a second order reaction
`t_(1//2)=(1)/("Rate constant" xx "initial concentration")=(1)/(ka)`
`=(1)/(10^(-4)"L mol"^(-1)"min"^(-1) xx10^(-2) "mol L"^(-1))`
`= 10^(6) min`.
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