For a chemical reaction `Ararr B`,the rate of the reaction is `2.0xx10^(-3) sec^(-1)`, when the initial concentration is `0.05 mol dm^(-3)`. The rate of the same reaction is `1.6xx10^(-2) mol dm^(-3) sec^(-1)`. When the initial concentration is `0.1` mol `dm^(3)`, find the order of reaction.

Options

A. 2
B. 0
C. 3
D. 1

Answer

C

Explanation

`r=k[A]^(n)`
`(1.6xx10^(-2))/(2xx10^(-3))=(k(0.1)^(n))/(k(0.05)^(n))`
or `8 = 2^(1) or 2^(3)=2^(n):. n=3`.