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A viral preparation was inactivated in a...

A viral preparation was inactivated in a chemical bath. The inactivated in a chemical bath. The inactivation process was found to the first order in virus concentration and at the beginning of the experiment `2.0%` of the virus was found to be inactivated per minute The k for the inactivated per minute The k for the inactivated process is (assume that there is no change in rate in the interval)

A

`2.00xx10^(-2) s^(-1)`

B

`3.3xx10^(-4) s^(-1)`

C

`3.0xx10^(-4) s^(-1)`

D

`3.0xx10^(-1) s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
V (virus) `rarr` Deactivated virus
`-(Delta[V])/(Deltat)=k[V]`
Here `-(Delta[V])/([Delta])=2.0%=(2)/(100)`
and `Delta t = 1 min = 60 s`
`:. K = -(Delta[V])/(Deltat[V])`
`=(2)/(100xx60)=3.3xx10^(-4)s`.
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