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The rate constant for the first order de...

The rate constant for the first order decomposition of ethylene oxide into `CH_(4)` and CO,

may be describe by
`log k("in" s^(-1))=14.34-(1.25xx10^(4)K)/T`
The activation energy of the reaction is

A

`4.8xx10^(-5) kJ "mol"^(-1)`

B

`4.8xx10^(5) kJ "mol"^(-1)`

C

`2.39xx10^(2) kJ "mol"^(-1)`

D

`2.39xx10^(5) kJ "mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`log k=logA=(E_(a))/(2.303RT)`
`log k=14.34-(12.5xx10^(4)K)/(T)`
From (i) and (ii)
`(E_(a))/(2.303R)=12.5xx10^(4)K`
`E_(a)=(12.5xx10^(4)K)xx(2.303)xx(8.314JK^(-1)"mol"^(-1))`
`=2.39xx10^(3)"kJ mol"^(-1)`.
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