A reaction has a rate constant of `0.25 "mol"^(-1)` L `s^(-1)` if the initial concentration of the reactant is `0.2` mol `L^(-1)` half life of the reaction is

Options

A. 15 s
B. 10 s
C. 20 s
D. 50 s

Answer

C

Explanation

From units of rate constant the reaction is of second order. For a second order reaction
`t_(1//2)=(1)/(ka)=((1)/(0.25xx0.2))s`
`=((100xx10)/(25xx2))s=20s`.