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What will be the total number of electro...

What will be the total number of electrons , protons and neutrons in the product formed by the loss of one `alpha`-particle `""_(92)^(238)U` ?

A

326

B

333

C

324

D

332

Text Solution

Verified by Experts

The correct Answer is:
C
`""_(92)^(238)Y rarr ""_(2)^(4)He + ""_(90)^(234)Th`
`" "`Product
In the product , protons=90, electrons =90 and neutrons = 234-90=144
So total number `=p+n+e`
`=90+90+144=324`
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