On bombarding ""(7)N^(14) with alpha-par...

On bombarding `""_(7)N^(14)` with `alpha`-particles, the nuclei of the product formed after the release of a proton will be

`""_(9)F^(17)`

`""_(8)O^(17)`

`""_(9)F^(18)`

`""_(8)N^(18)`

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The correct Answer is:

`""_(7)N^(14) + ""_(2)He^(4) rarr ""_(8)O^(17)+""_(1)H^(1)`

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