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For the nuclear reaction, .(0)n^(1) to ....

For the nuclear reaction, `._(0)n^(1) to ._(1)H^(1) + ?`, the missing nuclide is

A

`""_(33)As^(75)+_(2)He^(4) rarr ""_(35)Br ^(78)+_(0)n^(1)`

B

`""_(3)Li^(7)+_(2)He^(4) rarr ""_(35)Br^(78)+_(0)n^(1)`

C

`""_(88)Bi^(209)+_(0)n^(1) rarr ""_(20)Ca^(40)+_(1)H^(1)`

D

`""_(21)Sc^(45)+_(0)n^(1) rarr ""_(20)Ca^(45)+_(1)H^(1)`

Text Solution

Verified by Experts

The correct Answer is:
B

`""_(92)^(235)U + ""_(0)n^(1) to ?+ ""_(0)gamma^(0)`
Comparing the atomic numbers and mass numbers, we get `""_(92)^(236)U`.
`""_(94)^(239)Pu + 4""_(0)^(1)n rarr ""_(94)^(243)Pu + gamma`
Missing particles :` 4" "4 ""_(0)n^(1)`
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DINESH PUBLICATION-NUCLEAR AND RADIO CHEMISTRY-Evaluate Yourself
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