When .(17)Cl^(35) undergoes (n,p) reacti...

When `._(17)Cl^(35)` undergoes `(n,p)` reaction, the radioisotope formed is a)`._(15)P^(32)` b)`._(16)S^(35)` c)`._(16)S^(34)` d)`._(15)P^(34)`

`""_(15)P^(32)`

`""_(16)S^(35)`

`""_(16)S^(34)`

`""_(15)P^(34)`

Text Solution

Verified by Experts

The correct Answer is:

`""_(17)Cl^(35)+ ""_(0)n^(1) rarr ""_(16)S^(35) + ""_(1)H^(1)`

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