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If N(0) is the number of radioactive nuc...

If `N_(0)` is the number of radioactive nuclei initially present , then the number of nuclei remaining undecayed at the end of nth half life is

A

`2^(-n) N_(0)`

B

`2^(-n) N_(0)`

C

`2^(-n) N_(0)`

D

`2^(-n) N_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A
`N=N_(0)[(1)/(2)]^(n)`
`N=2^(-n)N_(0)`
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