The activity of an old piece of wood is just 1/4 of the fresh piece of wood. If `t_(1//2)` of C-14 is 6000 years, the age of the piece of wood is

Options

A. 6000 years
B. 3000 years
C. 9000 years
D. 12000 years

Answer

D

Explanation

`(N_(0))/(N)=(N_(0))/(N_(0)//4)=4`
`(N_(0))/(N)=2^(n)`
n= No. of half lives
`4 =2^(n)pn=2`
`therefore t=2 xx t_(1//2)`
`=2xx6000` years
=12,000 years