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If the mass defect of ""(4)^(9)X is 0.09...

If the mass defect of `""_(4)^(9)X` is 0.09 a.m.u. then the binding energy per nucleon is
(1 a.m.u= 931.5 MeV)

A

9.315 MeV

B

931.5 MeV

C

83.8 MeV

D

8.38 MeV

Text Solution

Verified by Experts

The correct Answer is:
A
Total binding energy= Mass defect `xx` 932.5 MeV
`0.09 xx 931.5 MeV`
=83.835 MeV
Binding energy per nucleon
`=(83.835)/(9)=MeV`
`=9.3148 underline(~) 9.315`
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DINESH PUBLICATION-NUCLEAR AND RADIO CHEMISTRY-Evaluate Yourself
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