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The weight of 1 curie .(82)Pb^(214) (t(1...

The weight of `1` curie `._(82)Pb^(214) (t_(1//2)=26.8 min)` in grams is

A

`3.1xx10^(-8)` g

B

`1.55xx10^(-8)` g

C

`6.2xx10^(-8)` g

D

`3.1xx10^(-10)` g

Text Solution

Verified by Experts

The correct Answer is:
A
`(-dN)/(dt)=(0.693)/(t_(1//2))xx(Wxx6.02xx10^(23))/("Mass No.")`
`3.7 xx 10^(10)=(0.693)/(26.8xx60)xx(Wxx6.02xx10^(23))/(214)`
`W=3.01xx10^(-8)` g.
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