A radioactive isotope decays to such a rate that after 96 min only 1/8th of the original amount remains. The value `t_(1//2)` of this nuclide is

Options

A. 12.0 min
B. 32.0 min
C. 24.0 min
D. 48.0 min

Answer

B

Explanation

`lambda=(2.303)/(lambda)"log"([N_(0)])/([N])=(2.303)/(96)"log"(1)/(1//8)`
`=(2.303)/(96)xx0.9=0.0216 "min"^(-1)`
`therefore t_(1//2)=(0.693)/(lambda)=(0.693)/(0.0216)=32.0` min.