Radioactivity of a radioactive element remains `1//10` of the original radioactivity after `2.303` seconds. The half life period is

Options

A. 2.303 seconds
B. 23.03 seconds
C. 0.693 seconds
D. 0.0693 seconds

Answer

C

Explanation

`lambda(2.303)/(t)"log"(N_(0))/(N_(t))=(2.303)/(2.303)"log"(1)/(1//10)`
`1xx"log"10=1`
`t_(t//2)=(0.693)/(lambda)=(0.693)/(1)=0.693`