An archeological sample of wood has half `C^(14)` activity as compared to that found in fresh wood of the same plant. The half life of `C^(14)` is 5770 years. The age of archiological sample of wood will be

Options

A. 5770 years
B. 2885 years
C. 11,540 years
D. 1445 years

Answer

A

Explanation

`N_(t)=N_(0)((1)/(2))^(n)`
`(N_(0))/(2)=N_(0)((1)/(2))^(n)" "[because N_(t)=(N_(0))/(2)]`
`(1)/(2)=((1)/(2))^(1) therefore n=1`
`T=t_(1//2)xxn=5770xx1=5770` years