A radioactive isotope decays at such a rate that after 96 min, only `1//8th` of the original amount remains.
The value of `t_(1//2)` of this nuclide is
a. 12 min b. 32 min c. 24 min d. 48 min

Options

A. 12.0 min
B. 32.0 min
C. 24.0 min
D. 48.0 min

Answer

B

Explanation

`1=(2.303)/(t) "log"(N_(0))/(N)`
`=(2.303)/(96)"log"(1)/(1//8)=(2.303)/(96)xx0.90`
`=0.0216 "min"^(-1)`
`therefore t_(1//2)=(0.693)/(lambda)=(0.693)/(0.0216)=32.0` min