In radioactive transformation `""_(92)U^(235) to ""_(82)Pb^(206)` , the number of `alpha` and `beta` particles emitted are

Options

A. `10 alpha, 6 beta`
B. 4 protons, 8 neutrons
C. 6 electrons, 8 protons
D. `6 beta, 8 alpha`

Answer

D

Explanation

`""_(92)U^(238) rarr ""_(82)Pb^(206) + m_(2)He^(4)+n""_(-1)e^(0^(-))`
`238=206+m implies m =8`
`92=82+2m-n`
`2m-n=10`
As `" "m=8 implies n=6`
`therefore alpha`-particle emitted, m=8
`beta`-particles emitted , n=6