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Number of neutrons i8n a parent nucleus ...

Number of neutrons i8n a parent nucleus `X`, which gives `._(7)^(14)N` after two sucessive `beta-` emission would be:

A

6

B

7

C

8

D

9

Text Solution

Verified by Experts

The correct Answer is:
D

`""_(a)^(b)X to ""_(7)^(14)N+2""_(-1)e^(0)`
`a=7-2=5`
b=14
`therefore ""_(a)^(b)X=""_(5)^(14)X`
Number of neutrons =14-5=9
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