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After 2 hr the radioactive substance bec...

After 2 hr the radioactive substance becomes 1/16 th of original amount. The `t_(1//2)` in minutes is

A

60 min

B

120 min

C

30 minutes

D

15 minutes

Text Solution

Verified by Experts

The correct Answer is:
C

`t=2 hrs = 2xx60 =120` min
`(N)/(N_(0))=(1)/(16), t_(1//2)=?`
`N=(N_(0))/(2^(n)) implies " "(N)/(N_(0))=(1)/(2^(n))`
`implies (1)/(16)=(1)/(2^(n)) implies " "n=4`
`n=(t)/(t_(1//2))implies t_(1//2)=(t)/(n)=(120 "min")/(4)`=30 min
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