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In the case of a radioisotope , the valu...

In the case of a radioisotope , the value of `t_(1//2)` and `lambda` are identical in magnitude. The value is

A

1/0.693

B

`(0.693)^(1//2)`

C

0.693

D

`(0.693)^(1//2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`(t)/(t_(1//2))=(0.693)/(lambda)therefore t_(1//2)xxlambda=0.693`
Let `t_(1//2)=lambda=x` (Say)
or `"x" xx "x"=0.693` i.e., `x^(2)=0.693`
or `x=(0.693)^(1//2)`
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