Home
Class 11
CHEMISTRY
If N(0) =1 gm then after how many half l...

If `N_(0)` =1 gm then after how many half lives N t will be 0.25 gm ?

A

2

B

3

C

1

D

4

Text Solution

Verified by Experts

The correct Answer is:
A
`N_(0)=1 g , N_(t)=0.25 g`
`N_(t)=(N_(0))/(2^(n))`
`0.25=(1)/(2^(n))`
`2^(n)=(1)/(0.25)=4=2^(2)`
`therefore " "n=2`
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR AND RADIO CHEMISTRY

    DINESH PUBLICATION|Exercise Selected Straight Objected Type MCQs|26 Videos

  • NUCLEAR AND RADIO CHEMISTRY

    DINESH PUBLICATION|Exercise Linked Comprehension Type MCQs|9 Videos

  • NUCLEAR AND RADIO CHEMISTRY

    DINESH PUBLICATION|Exercise Evaluate Yourself|45 Videos

  • NOMENCLATURE OF ORGANIC COMPOUNDS

    DINESH PUBLICATION|Exercise MCQs|13 Videos

  • ORGANIC CHEMISTRY - SOME BASIC PRINCIPLES & TECHNIOUES

    DINESH PUBLICATION|Exercise PURIFICATION & CHARACTERISATION OF ORGANIC COMPOUNDS|38 Videos

Similar Questions

Explore conceptually related problems

Consider a radioactive substance. The fraction of its quantity that remains after t half lives is given by 3^(-t) . After how many half lives will the fraction be 1/243 of the original?

Half-life of radium is 1,620 years. After how many half-lives 0.75 mg of radium will be disintegrated out of its initial m ass of 1 mg?

Half life of a radioactive elemets is 12.5 hour and its quantity is 256 gm. After how much time is quantity will remain 1 gm ?

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) Half life of .^(60)Co is 5.3 years, the time taken for 99.9% decay will be

If N_(0) is the original mass of the substance of half - life period t_(1//2) = 5 year then the amount of substance left after 15 year is

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) Which "is"//"are" true about the decay cosntant?

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) Amount of radioactive elements (activity) decreases with passage of time as

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) The rate of radioactive decay is

DINESH PUBLICATION-NUCLEAR AND RADIO CHEMISTRY-Revision Questions from Competitive Exams
  1. A overset(-2beta)to overset(-alpha)to C. Relation between A and C is

    Text Solution

    |

  2. It t(1//2) of A is 1000 yrs, then 'A' left after t=2000 years

    Text Solution

    |

  3. If N(0) =1 gm then after how many half lives N t will be 0.25 gm ?

    Text Solution

    |

  4. ""(92)^(235)U+X to Ba +Kr +3 ""(1)^(0)n X is

    Text Solution

    |

  5. Alpha particles are

    Text Solution

    |

  6. Most radioactive is

    Text Solution

    |

  7. Which of the following isotopes of uranium is most radioactive ?

    Text Solution

    |

  8. In the nuclear reaction ""(13)Al^(27)+""(2)He^(4) to ""(14)X^(30)+"...

    Text Solution

    |

  9. The product obtained after positron emission from ""(31)Ga^(68) is

    Text Solution

    |

  10. One gm of an element decays by beta-emission to 0.125 gm in 200 years...

    Text Solution

    |

  11. Isotopes are

    Text Solution

    |

  12. The noble gas used in atomic reactors is

    Text Solution

    |

  13. The atomic number (A) and mass number (M) of the nuclide formed when t...

    Text Solution

    |

  14. The process, ""(1)H^(2) +""(1)H^(3) to ""(2)He^(4) +""(0)n^(1) represe...

    Text Solution

    |

  15. Given that radioactive species decays according to the exponential law...

    Text Solution

    |

  16. Fusion bomb involves

    Text Solution

    |

  17. The element usef fro dating the ancient remains is

    Text Solution

    |

  18. If the mass defect of ""(4)^(9)X is 0.099 a.m.u. , then binding energy...

    Text Solution

    |

  19. ""(27)Co^(60) is radioactive because

    Text Solution

    |

  20. A heavy element has atomic number X and mass number Y . Correct relati...

    Text Solution

    |