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If the mass defect of ""(4)^(9)X is 0.09...

If the mass defect of `""_(4)^(9)X` is 0.099 a.m.u. , then binding energy per nucelon is (1 a.m.u, 931.5 MeV)

A

10.25 MeV

B

931.5 MeV

C

83.0 MeV

D

8.38 MeV

Text Solution

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The correct Answer is:
A
`Deltam=0.099` a.m.u.
`E=0.099 xx 931.5` MeV
E(per nucleon)`=(0.099xx931.5)/(9)` MeV
(No. of nucleons in `""_(4)^(9)X=9`)
`=(99xx931.5)/(9xx1000)=10.2465` MeV
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