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An artifical radioactive isotope gave ""...

An artifical radioactive isotope gave `""_(7)^(14)N` after two successive `beta`-particle emissions. The number of neutrons in the parent nucleus must be

A

9

B

14

C

5

D

7

Text Solution

Verified by Experts

The correct Answer is:
A
`""_(a)X^(b)to ""_(7)N^(14)+ 2 - ""_(1)beta^(0)`
a=7-2=5
b=14
`therefore ""_(a)X^(b)=""_(5)B^(14)`
`therefore` No. of neutrons in B-14 =14 -5 =9
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