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Consider the following nuclear reactions...

Consider the following nuclear reactions:
`""_(92)""^(238)Mto.""_(y)""^(x)N+2.""_(2)""^(4)He, ""_(x)""^(y)Nto ""_(B)""^(A)L+2beta""^(+)`
The number of neutrons in the element L is

A

142

B

146

C

140

D

144

Text Solution

Verified by Experts

The correct Answer is:
C

`""_(92)M^(238) to ""_(y)N^(x) + 2""_(2)He^(4)`
238=x+8
x=230
y+4=92
y+4=92
y=88
`""_(88)N^(230) to ""_(B)L^(A) + 2+underset("Positron")(""_(1)beta^(0))`
A=230
B+2 =88
B=88-2=86
`therefore ""_(B)L^(A)=""_(86)L^(228)`
No. of neutrons in L =230 -86 =134
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