`._(92)U^(238)` emits `8 alpha-` particles and `6 beta-` particles. The `n//p` ratio in the product nucleus is a)`(62)/(41)` b)`(60)/(41)` c)`(61)/(42)` d)`(62)/(42)`

Options

A. 60/41
B. 61/40
C. `62//41`
D. `1//32`

Answer

C

Explanation

`""_(92)^(238)U to 8""_(2)^(4)He + 6 ""_(-1)e^(0) + ""_(82)^(206)X`
Number of neutrons in X = 206-82 =124
n/p ratio of end nucleus is 124/82 or 62/41.