What will be the binding energy of `""^(16)O` , if the mass defect is 0.210 amu ?

Options

A. `1.89 xx 10^(10) "J mol"^(-1)`
B. `1.89 xx 10^(15) "J mol"^(-1)`
C. `1.89 xx 10^(14) "J mol"^(-1)`
D. `1.89 xx 10^(13) "J mol"^(-1)`

Answer

D

Explanation

`Deltam=0.210 ` amu
`=0.210 xx 1.66057 xx 10^(-27)` kg
`DeltaE=Delta m C^(2)`
`=(0.210xx1.66057 xx 10^(-27) kg )xx(3xx10 ms^(-1))^(2)`
`=3.13847 xx 10^(-11) J`
`DeltaE` (per mole)=`3.13847 xx 10^(-11) J xx 6.022xx10^(23) "mol"^(-1)`
`=18.899xx10^(12) J"mol"^(-1)`
`=1.889 xx 10^(13) J "mol"^(-1)`