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.(13)Al^(27) is a stable isotope. .(13)A...

`._(13)Al^(27)` is a stable isotope. `._(13)Al^(29)` is expected to disintegrate by

A

`alpha`-emission

B

`beta`-emission

C

positron emission

D

Proton emission

Text Solution

Verified by Experts

The correct Answer is:
B

No. of neutrons (N) and protons (P) in `""_(13)^(29)Al ` are 16 and 13 respectively . As N/P ratio is more than 1 , the expected mode of decay is `beta`-emission .
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