How many hour are required for a current of `3.0` ampere to decompose `18 g` water?

Options

A. 6 h
B. 12 h
C. 18 h
D. 24 h

Answer

B

Explanation

`H_(2)O to 2H^(+) + O^(2-)`
Thus number of moles of electrons required for decomposition of water =2 moles Quantity of electricity or change required `=2 xx 96800` C
Time `=(2xx96500)/(3xx60xx60)=18` hours