If the nuclear radius of `.^27 A1` is `3.6` Fermi, the approximate nuclear radius of `64 Cu` in Fermi is :

Options

A. 1 Fermi
B. 5.6 Fermi
C. 6.5 Fermi
D. 3.8 Fermi

Answer

B

Explanation

`R=R_(0)A^(1//3)=1.4xx10^(-13)(64)^(1//3)`
`=5.6xx10^(-13) cm`
`=5.6` Fermi (`because` Fermi `=10^(-13) cm`)