on passing a current of 1.0 ampre for 16 min and 5 sec through one litre solution of `CuCl_(2)` all the copper of the solution was solution was peposited at cathode. The strength of `CuCl_(2)` solution was (Molar mass of Cu=63.5 faraday constant =96500 `C mol^(-1)`)

Options

A. 0.07 M
B. 0.2 N
C. 0.005 N
D. 0.02 N

Answer

C

Explanation

`Q=IxxT`
`=1Axx965s=965 C`
`Cu^(2+)+underset(2xx96500 C)(2e^(-))to underset(1 "mol")(Cu)`
`2 xx 96500 C `deposit copper = 1 mol
965 C deposite copper `=5xx10^(-3)` mol
`therefore` One litre of `CuCl_(2)` solution contain `=5xx10^(-3)` mol of solute
`therefore` Molarity of solution =0.005 M